LINQ-to-Entities Include的奇怪行为

我意识到我不完全理解LINQ-to-Entities中的Include方法。

例如，以下面的两个代码片段为例。我希望它们产生相同的输出(尽管第一个版本可能更有效，因为它避免了JOIN s)。

// Snippet 1
using (var db = new Db()) {
  var author = db.Authors.First();
  db.LoadProperty<Author>(author, o => o.Books);
  foreach (var book in author.Books) {
    db.LoadProperty<Book>(book, o => o.Editions);
    foreach (var edition in book.Editions)
      Response.Write(edition.Id + " - " + edition.Title + "<br />");
  }
}
Response.Write("<br />");
// Snippet 2
using (var db = new Db()) {
  var author = db.Authors.Include("Books.Editions").First();
  foreach (var book in author.Books) {
    foreach (var edition in book.Editions)
      Response.Write(edition.Id + " - " + edition.Title + "<br />");
  }
}

但是每个片段的输出是不同的:

1 - Some Book First Edition
2 - Another Book First Edition
3 - Another Book Second Edition
4 - Another Book Third Edition
8 - Some Book First Edition
9 - Another Book First Edition

第一个片段正确地输出{Edition Id} - {Edition Title}，而第二个片段意外地输出{Book Id} - {Edition Title}，并且只给出每本书的第一版。

怎么回事?是否有一种方法可以使用Include实现所需的输出?

编辑1: MySql数据看起来像(更正):

Authors         = { { Id = 1, Name = "Some Author" } }
Books           = { { Id = 8, AuthorId = 1 },
                    { Id = 9, AuthorId = 1 } }
Editions        = { { Id = 1, Title = "Some Book First Edition" },
                    { Id = 2, Title = "Another Book First Edition" },
                    { Id = 3, Title = "Another Book Second Edition" },
                    { Id = 4, Title = "Another Book Third Edition" } }
EditionsInBooks = { { BookId = 8, EditionId = 1 },
                    { BookId = 9, EditionId = 2 },
                    { BookId = 9, EditionId = 3 },
                    { BookId = 9, EditionId = 4 } }

请注意，没有Edition与Id = 8或Id = 9。

上面的代码是我的完整代码，在Page_Load中为一个空的测试页。

EDIT 2:我已经测试了以下内容，它们没有区别:

1. var author = db.Authors.Include("Books.Editions").AsEnumerable().First();
2. var author = db.Authors.Include("Books.Editions").Single(o => o.Id == 1);
3. var author = db.Authors.Include("Books").Include("Books.Editions").First();

EDIT 3:如果我启用延迟加载，下面的工作(在代码片段2中):

var author = db.Authors.First();

(我想这实际上与代码片段1的操作相同)

但是，不管是否延迟加载，这仍然返回奇怪的输出:

var author = db.Authors.Include("Books.Editions").First();

EDIT 4:很抱歉，我把上面的表结构表达错了。(我正经历着这样的日子。)现在它被修正了，以显示多对多关系。请参见编辑1

还有

的输出

((ObjectQuery)db.Authors.Include("Books.Editions").AsEnumerable())
  .ToTraceString()

SELECT
  `Project1`.`Id`,
  `Project1`.`Name`,
  `Project1`.`C2` AS `C1`,
  `Project1`.`id1`,
  `Project1`.`AuthorId`,
  `Project1`.`C1` AS `C2`,
  `Project1`.`id2`,
  `Project1`.`Title`
FROM (SELECT
  `Extent1`.`Id`,
  `Extent1`.`Name`,
  `Join2`.`Id` AS `id1`,
  `Join2`.`AuthorId`,
  `Join2`.`Id` AS `id2`,
  `Join2`.`Title`,
   CASE WHEN (`Join2`.`Id` IS NULL) THEN (NULL)
        WHEN (`Join2`.`BookId` IS NULL) THEN (NULL)
        ELSE (1) END AS `C1`,
   CASE WHEN (`Join2`.`Id` IS NULL) THEN (NULL)
        ELSE (1) END AS `C2`
   FROM `authors` AS `Extent1`
     LEFT OUTER JOIN (SELECT
       `Extent2`.`Id`,
       `Extent2`.`AuthorId`,
       `Join1`.`BookId`,
       `Join1`.`EditionId`,
       `Join1`.`Id` AS `Id1`,
       `Join1`.`Title`
       FROM `books` AS `Extent2`
       LEFT OUTER JOIN (SELECT
         `Extent3`.`BookId`,
         `Extent3`.`EditionId`,
         `Extent4`.`Id`,
         `Extent4`.`Title`
         FROM `editionsinbooks` AS `Extent3`
         INNER JOIN `editions` AS `Extent4`
           ON `Extent4`.`Id` = `Extent3`.`EditionId`) AS `Join1`
       ON `Extent2`.`Id` = `Join1`.`BookId`) AS `Join2`
     ON `Extent1`.`Id` = `Join2`.`AuthorId`) AS `Project1`
   ORDER BY
     `Project1`.`Id` ASC,
     `Project1`.`C2` ASC,
     `Project1`.`id1` ASC,
     `Project1`.`C1` ASC

CASE语句很有趣，因为我的MySql字段都不是可空的。

using (var db = new Db()) {
    var author = db.Authors.Include("Books.Editions").AsEnumerable().First();
    foreach (var book in author.Books)
    {
        foreach (var edition in book.Editions)
        {
            Response.Write(edition.Id + " - " + edition.Title + "<br />");
        }
    }
}

var sql = ((System.Data.Objects.ObjectQuery)db.Authors.Include("Books.Editions").AsEnumerable().First()).ToTraceString();