使包装器类的扩展方法/构造函数泛型
本文关键字:方法 构造函数 泛型 扩展 包装 | 更新日期: 2023-09-27 18:14:22
在一个服务(,我不能改变)我有两个对象类Bar
和Baz
大多相似的属性(,但遗憾的是没有,他们不派生自相同的基类或继承自相同的接口…是的——哑巴),以及与其相关的BarQux
和BazQux
属性相关的依赖类:
public class Bar public class Baz
{ {
public int ID { get; set; } public int ID { get; set; }
public bool Active { get; set; } public bool Active { get; set; }
public int BarQux { get; set; } public int BazQux { get; set; }
... ...
} }
public class Qux
{
public int ID { get; set; } // Corresponds to BarQux and BazQux
public string Name { get; set; }
}
在WPF屏幕中,我将每种类型(Baz
和Bar
)的列表绑定到两个单独的ListViews。我需要每个有一个额外的Selected
复选框列。为此,我创建了一个包装器类,其中包含常用属性、附加的Selected
属性和每个属性的构造函数:
public class Foo
{
public Foo(Bar bar, Qux qux)
{
this.Active = bar.Active;
this.FooQux = string.Format("{0} - {1}", qux.ID, qux.Name);
...
}
public Foo(Baz baz, Qux qux)
{
this.Active = baz.Active;
this.FooQux = string.Format("{0} - {1}", qux.ID, qux.Name);
...
}
public bool Selected { get; set; }
public int ID { get; set; }
public bool Active { get; set; }
public string FooQux { get; set; }
...
}
为了将Baz
和Bar
类的集合转换为Foo
的集合,我创建了以下扩展方法:
public static List<Foo> ToFoo(this IEnumerable<Bar> bars, IEnumerable<Qux> quxs)
{
List<Foo> foos = new List<Foo>();
foreach (Bar bar in bars)
{
Foo foo = new Foo(bar, quxs.Single(qux => qux.ID == bar.BarQux));
foos.Add(foo);
}
return foos;
}
public static List<Foo> ToFoo(this IEnumerable<Baz> bazs, IEnumerable<Qux> quxs)
{
List<Foo> foos = new List<Foo>();
foreach (Baz baz in bazs)
{
Foo foo = new Foo(baz, quxs.Single(qux => qux.ID == baz.BazQux));
foos.Add(foo);
}
return foos;
}
问题:
如何使其泛型?
理论、实现和错误:
由于构造函数除了
Bar
和Baz
参数之外几乎是相同的,我可以以某种方式使用泛型T
来创建一个构造函数并且仍然抓取属性吗?public class Foo<T> { public Foo(T obj, Qux qux) { this.Active = obj.Active; // 'T' does not contain a definition for 'Active'... this.Qux = string.Format("{0} - {1}", qux.ID, qux.Name); ... } ... }
更改构造函数以接收
Qux
对象的整个集合并在那里执行quxs.Single(qux => qux.ID == object.ObjectQux)
逻辑。然后将这些扩展方法做成一个泛型方法,如下所示。public static List<Foo> ToFoo<T>(this IEnumerable<T> objCollection, IEnumerable<Qux> quxs) { List<Foo> foos = new List<Foo>(); foreach (T obj in objCollection) { Foo foo = new Foo(obj, quxs); // The best overloaded method... has some invalid arguments. foos.Add(foo); } return foos; }
1和2组合?还有我没想到的吗?
如果您的属性有限,并且列表中的项目数量也很少,那么您可以使用Reflection
。由于您将在WPF中使用此功能,我还建议将该进程移动到单独的后台线程中。
通用Foo
public class Foo<T>
{
public Foo(T obj, Qux qux)
{
//this.Active = obj.Active;
var fooProps = GetType().GetProperties().ToList();
var tProps = typeof(T).GetProperties()
.Where(p =>
{
var w = fooProps.FirstOrDefault(f => f.Name == p.Name);
return w != null;
}).ToList();
foreach (var propertyInfo in tProps)
{
var val = propertyInfo.GetValue(obj);
fooProps.First(e => e.Name == propertyInfo.Name).SetValue(this, val);
}
this.FooQux = string.Format("{0} - {1}", qux.ID, qux.Name);
}
public bool Selected { get; set; }
public int ID { get; set; }
public bool Active { get; set; }
public string FooQux { get; set; }
}
扩展方法
public static IEnumerable<Foo<Bar>> ToFoo(this IEnumerable<Bar> bars, IEnumerable<Qux> quxs)
{
return bars.
Select(bar => new Foo<Bar>(bar, quxs.Single(qux => qux.ID == bar.BarQux))).ToList();
}
public static IEnumerable<Foo<Baz>> ToFoo(this IEnumerable<Baz> bazs, IEnumerable<Qux> quxs)
{
return bazs.
Select(baz => new Foo<Baz>(baz, quxs.Single(qux => qux.ID == baz.BazQux))).ToList();
}
public static IEnumerable<Qux> ToQuxes(this IEnumerable<BazQux> bazQuxs)
{
return bazQuxs.Select(b => new Qux(typeof(BazQux), b)).ToList();
}
public static IEnumerable<Qux> ToQuxes(this IEnumerable<BarQux> barQuxes )
{
return barQuxes.Select(b => new Qux(typeof(BarQux), b)).ToList();
}
同样,您也可以将BarQux
或BazQux
转换为非泛型Qux
类。
public class Qux
{
public int ID { get; set; } // Corresponds to BarQux and BazQux
public string Name { get; set; }
public Qux(Type type, object obj)
{
var ob = Convert.ChangeType(obj, type);
var quxProps = GetType().GetProperties();
var obProps = ob.GetType().GetProperties()
.Where(p =>
{
var w = quxProps.FirstOrDefault(f => f.Name == p.Name);
return w != null;
}).ToList();
foreach (var propertyInfo in obProps)
{
var val = propertyInfo.GetValue(obj);
quxProps.First(e => e.Name == propertyInfo.Name).SetValue(this, val);
}
}
}
你可以调用ToFoo
扩展方法,瞧,你有一个Foo列表。
您还可以使用Qux
类
我真的看不出这样做有什么好处。
如果你坚持使用泛型,你可以对T做一些类型检查,像这样:
public class Foo<T>
{
public Foo(T obj, Qux qux)
{
var baz = obj as Baz;
var bar = obj as Bar;
Active = baz != null && baz.Active || bar != null && bar.Active;
this.FooQux = string.Format("{0} - {1}", qux.ID, qux.Name);
}
public bool Selected { get; set; }
public int ID { get; set; }
public bool Active { get; set; }
public string FooQux { get; set; }
}
或:
public static List<Foo> ToFoo<T>(this IEnumerable<T> objCollection, IEnumerable<Qux> quxs)
{
List<Foo> foos = new List<Foo>();
foreach (T obj in objCollection)
{
var baz = obj as Baz;
var bar = obj as Bar;
Foo foo = null;
if(baz != null)
foo = new Foo(baz, quxs.Single(qux => qux.ID == baz.BazQux));
if(bar != null)
foo = new Foo(bar, quxs.Single(qux => qux.ID == bar.BarQux));
if(foo != null)
foos.Add(foo);
}
return foos;
}
但是这显然并不比你已经拥有的好多少,如果T不是Bar或Baz(没有显示),你将不得不做一些异常处理,这将使你暴露于潜在的运行时失败。你也可以使用反射,但效果是一样的。
你正在寻找不幸的是c#是不可能的。唯一可以避免这种情况的方法是,如果界面是像Golang一样的duck-typed,但情况并非如此。
根据Sandesh的建议,最终结果:
public class Foo<T>
{
public Foo() {}
public Foo(T obj, IEnumerable<Qux> quxs, string quxPropName)
{
var fooProps = GetType().GetProperties().ToList();
var tProps = typeof(T).GetProperties()
.Where(p =>
{
var w = fooProps.FirstOrDefault(f => f.Name == p.Name);
return w != null;
}).ToList();
foreach (var propertyInfo in tProps)
{
var val = propertyInfo.GetValue(obj, null);
fooProps.First(e => e.Name == propertyInfo.Name).SetValue(this, val, null);
}
int id = (int)typeof(T).GetProperty(quxPropName).GetValue(obj, null);
Qux qux = quxs.Single(q => q.ID == id);
this.FooQux = string.Format("{0} - {1}", qux.ID, qux.Name);
}
public bool Selected { get; set; }
public int ID { get; set; }
public bool Active { get; set; }
public string FooQux { get; set; }
}
和泛型扩展方法:
public static List<Foo<T>> ToFoo<T>(this IEnumerable<T> list, IEnumerable<Qux> quxs, string quxPropName)
{
List<Foo<T>> foos = null;
try
{
foos = list.Select(obj => new Foo<T>(obj, quxs, quxPropName)).ToList();
}
catch
{
foos = new List<Foo<T>>();
}
return foos;
}
和用法:
List<Foo<Bar>> bars = barCollection.ToFoo(quxCollection, "BarQux");
List<Foo<Baz>> bazs = bazCollection.ToFoo(quxCollection, "BazQux");