c#获得所有同名元素的列表——XML反序列化
本文关键字:列表 XML 反序列化 元素 | 更新日期: 2023-09-27 18:15:48
我尝试获得xml文件中所有声音元素的列表。
我得到了所有的标记,但当我试图得到所有的元素与标签声音我没有得到任何东西。列表始终为0。
根类[XmlArray("markers")]
[XmlArrayItem("marker")]
public List<WaypointInfo> markers = new List<WaypointInfo>();
[XmlArray("pattern")]
[XmlArrayItem("sound")]
public List<SoundInfo> soundsInfo = new List<SoundInfo> ();
/// <summary>
/// The file extension.
/// </summary>
public static readonly string fileExtensionMp3 = "*.mp3";
public static FileLoader loadInformationXML(string filePath){
//Define the rootclass
XmlSerializer serializer = new XmlSerializer (typeof(FileLoader));
//Create inputstream
FileStream fl = new FileStream (filePath, FileMode.Open);
//Extract the stream and save it into our root class
FileLoader xmlData = serializer.Deserialize (fl) as FileLoader;
//Close the inputstream
fl.Close ();
return xmlData;
}
标记数组列表是正确的,但是其他的声音列表总是空的。
类WaypointsInfousing UnityEngine;
using System.Collections.Generic;
using System.Xml.Serialization;
public class WaypointInfo {
[XmlAttribute("name")]
public string markerName;
public Pattern pattern = new Pattern();
}
类Soundinfo using UnityEngine;
using System.Xml.Serialization;
using System.Collections;
public class SoundInfo {
/// <summary>
/// The minimum distance that triggers this sound.
/// </summary>
[XmlAttribute("distance")]
public float distance;
/// <summary>
/// When this sound has been played the last time, in runtime milliseconds.
/// </summary>
public float lastPlayed;
/// <summary>
/// If this sound should be looped.
/// </summary>
public bool looped;
}
和XML文件
<soundpackage>
<markers>
<marker name="bird">
<pattern name="aPattern">
<sound distance="10">bird.mp3</sound>
<sound distance="10">bird.mp3</sound>
</pattern>
</marker>
</markers>
</soundpackage>
您的根节点是否有这样的代码xmlns=http;//somepath
?然后处理名称空间。当您得到零结果并且您确定正确引用它时,必须考虑名称空间。
我不熟悉Xml序列化。因此,我查找XML序列化的名称空间。下面是另一个StackOverflow线程的例子。