我如何将IntPtr转换为UIntPtr

我试着像这样投射它:

UIntPtr x = (UIntPtr)intPtr;

…但是编译器对它不太满意，并返回了一个编译错误。

我需要进行转换，因为RegOpenKeyEx的p/Invoke签名需要UIntPtr:

  [DllImport("advapi32.dll", CharSet = CharSet.Auto)]
  public static extern int RegOpenKeyEx(
    UIntPtr hKey,
    string subKey,
    int ulOptions,
    int samDesired,
    out UIntPtr hkResult);

为了得到一个句柄，我使用safehandle . dangerouhandle()返回一个IntPtr:

   /// <summary>
    /// Get a pointer to a registry key.
    /// </summary>
    /// <param name="registryKey">Registry key to obtain the pointer of.</param>
    /// <returns>Pointer to the given registry key.</returns>
    IntPtr _getRegistryKeyHandle(RegistryKey registryKey)
    {
        //Get the type of the RegistryKey
        Type registryKeyType = typeof(RegistryKey);
        //Get the FieldInfo of the 'hkey' member of RegistryKey
        System.Reflection.FieldInfo fieldInfo =
            registryKeyType.GetField("hkey", System.Reflection.BindingFlags.NonPublic | System.Reflection.BindingFlags.Instance);
        //Get the handle held by hkey
        SafeHandle handle = (SafeHandle)fieldInfo.GetValue(registryKey);
        //Get the unsafe handle
        IntPtr dangerousHandle = handle.DangerousGetHandle();
        return dangerousHandle;
    }