访问对象图中的根类封装属性

本文关键字：封装 属性 对象图 访问 | 更新日期: 2023-09-27 18:27:24

我目前正在编写一个冒险游戏创建者框架，到目前为止我有以下课程：

// Base class that represents a single episode from a complete game.
public abstract class Episode : IEpisode
{
    public RoomList Rooms {get; }
    public ArtefactList Artefacts {get; }
    public Episode()
    {
        Rooms = new RoomList();
        Artefacts = new ArtefactList();
    }
}
// This is a list of all objects in the episode.
public ArtefactList : List<IArtefact>
{
    public IArtefact Create( UInt32 id, String text )
    {
        IArtefact art = new Artefact( id, text );
        base.Add( art );
        return art;
    }
}
// This is a list of all rooms in the episode.
public RoomList : List<IRoom> 
{   
    public IRoom Create( UInt32 id, String text )
    {
        IRoom rm = new Room( id, text );
        base.Add( rm );
        return rm;
    }
}
public class Room : IRoom
{
    public UInt32 Id { get; set; }
    public String Text { get; set; }
    public IList<IArtefact> Artefacts
    {
        get
        {
            return ???what??? // How do I access the Artefacts property from
                                // the base class:
                                //  (Room --> RoomList --> Episode)
        }
    }   
}
public class Artefact : IArtefact
{
    public UInt32 Id { get; set; }
    public String Text { get; set; }
    public IRoom CurrentRoom { get; set; }
}
public interface IArtefact
{
    UInt32 Id { get; set; }
    String Text { get; set; }
    IRoom CurrentRoom { get; set; }
}
public interface IRoom
{
    UInt32 Id { get; set; }
    String Text { get; set; }
    IList<IArtefact> Artefacts {get; }
}

我想知道的是，Room类应该如何访问Episode类的封装的Artefacts属性，而不必一直向下传递对Episode的引用，即Episode->RoomsList->Room。

访问对象图中的根类封装属性

房间和工艺品之间存在一对多的关系。因此，您必须在RoomList中初始化此关系。创建方法：

public IRoom Create( UInt32 id, String text , ArtefactList artefacts)
{
    IRoom rm = new Room( id, text , artefacts);
    base.Add( rm );
    return rm;
}

创建房间时，您可以这样做：

var episode = new Episode();
episode.Rooms.Create(1, "RoomText", episode.Artefacts);

您应该对ArtefactList执行同样的操作。创建为Artefact需要IRoom实例。

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