笛卡尔数组的平方

本文关键字：数组笛卡尔 | 更新日期: 2023-09-27 18:13:04

我如何从一些数组中获得有序的元素对，使用LINQ?例如,我:

int[] d = { 1, 2, 3 };

我需要

{{1,1}， {1,2}， ....， {3,3}}

我尝试了LINQ查询，但它返回

{{1}, {2,}, {3}, {1}, {2,}, {3}, {1}, {2,}, {3,3}}

var pairs = d.SelectMany(a => d.Select(b => new[] { a, b }));

笛卡尔数组的平方

像这样:

var result = d.SelectMany(a => d, Tuple.Create)
              .Where(c=> c.Item1 <= c.Item2).ToArray();

此代码有效

        int[] d = { 1, 2, 3 };
        var query = (from elem1 in d
                     from elem2 in d 
                     where elem1>= elem2
                     select elem1< elem2? new List<int>() { elem1, elem2 }: new List<int>() { elem2, elem1 }
                     ).Distinct().ToArray();