向 url 发送 xml 请求并接收返回的 xml 响应

本文关键字：xml 返回 响应 url 发送 请求 | 更新日期: 2024-10-31 10:07:52

>我正在尝试向 url 发送 xml 请求，响应也将是 xml 响应。我知道如何从 MVC 应用程序调用服务终结点，但我不确定如何调用此 URL 以及如何读取它将给我的内容。 这就是我目前所拥有的。 这是正确的方向吗？

请求：

<CityStateLookupRequest USERID=”xxxxxxxx”>
<ZipCode ID="0">
<Zip5>90210</Zip5>
</ZipCode>
</CityStateLookupRequest>

响应： 

<CityStateLookupResponse>
<ZipCode ID="0">
<Zip5>90210</Zip5>
<City>BEVERLY HILLS</City>
<State>CA</State>
</ZipCode>
</CityStateLookupResponse>

C# 代码： 

var xmlRequest = new XElement("CityStateLookupRequest",
                new XAttribute("USERID", "XXXXXXXXX"),
                new XElement("ZipCode",
                    new XAttribute("ID", "0"),
                    new XElement("Zip5", "43065")));    
HttpWebRequest request = (HttpWebRequest)WebRequest.Create(" http://production.shippingapis.com/ShippingAPI.dll");
byte[] bytes = System.Text.Encoding.ASCII.GetBytes(xmlRequest.ToString());
request.ContentType = "text/xml; encoding='utf-8'";
request.ContentLength = bytes.Length;
request.Method = "POST";
Stream requestStream = request.GetRequestStream();
requestStream.Write(bytes, 0, bytes.Length);
requestStream.Close();
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
if (response.StatusCode == HttpStatusCode.OK)
{
    var xmlDoc = new XmlDocument();
    xmlDoc.Load(response.GetResponseStream());
}

向 url 发送 xml 请求并接收返回的 xml 响应

这是您可以执行此操作的一种方法，它基本上是一个表单帖子。

var xmlRequest = new XElement("CityStateLookupRequest",
    new XAttribute("USERID", "XXXXXXXXX"),
    new XElement("ZipCode",
        new XAttribute("ID", "0"),
        new XElement("Zip5", "43065")));
HttpWebRequest request = (HttpWebRequest)WebRequest.Create("http://production.shippingapis.com/ShippingAPI.dll");        
// parameters to post - other end expects API and XML parameters
var postData = new List<KeyValuePair<string, string>>();
postData.Add(new KeyValuePair<string, string>("API", "CityStateLookup"));
postData.Add(new KeyValuePair<string, string>("XML", xmlRequest.ToString()));    
// assemble the request content form encoded (reference System.Net.Http)
HttpContent content = new FormUrlEncodedContent(postData);
// indicate what we are posting in the request
request.Method = "POST";
request.ContentType = "application/x-www-form-urlencoded";
request.ContentLength = content.Headers.ContentLength.Value;
content.CopyToAsync(request.GetRequestStream()).Wait();                        
// get response
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
if (response.StatusCode == HttpStatusCode.OK)
{
    // as an xml: deserialise into your own object or parse as you wish
    var responseXml = XDocument.Load(response.GetResponseStream());
    Console.WriteLine(responseXml.ToString());
}
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